URL中出现空格，等字符会乱码，这个是见到的一个比较不错的处理方式。调用时，把要传递的参数通过这个js方法转化一下就可以转化为%xx组成的一系列字符 服务端正常获取 有兴趣的可以试一下 ，具体代码如下：
function encodeURL(str){
var s0, i, s, u;
s0 = ""; // encoded str
for (i = 0; i < str.length; i++){ // scan the source
s = str.charAt(i);
u = str.charCodeAt(i); // get unicode of the char
if (s == " "){s0 += "+";} // SP should be converted to "+"
else {
if ( u == 0x2a || u == 0x2d || u == 0x2e || u == 0x5f || ((u >= 0x30) && (u <= 0x39)) || ((u >= 0x41) && (u <= 0x5a)) || ((u >= 0x61) && (u <= 0x7a))){ // check for escape
s0 = s0 + s; // don\'t escape
}
else { // escape
if ((u >= 0x0) && (u <= 0x7f)){ // single byte format
s = "0"+u.toString(16);
s0 += "%"+ s.substr(s.length-2);
}
else if (u > 0x1fffff){ // quaternary byte format (extended)
s0 += "%" + (oxf0 + ((u & 0x1c0000) >> 18)).toString(16);
s0 += "%" + (0x80 + ((u & 0x3f000) >> 12)).toString(16);
s0 += "%" + (0x80 + ((u & 0xfc0) >> 6)).toString(16);
s0 += "%" + (0x80 + (u & 0x3f)).toString(16);
}
else if (u > 0x7ff){ // triple byte format
s0 += "%" + (0xe0 + ((u & 0xf000) >> 12)).toString(16);
s0 += "%" + (0x80 + ((u & 0xfc0) >> 6)).toString(16);
s0 += "%" + (0x80 + (u & 0x3f)).toString(16);
}
else { // double byte format
s0 += "%" + (0xc0 + ((u & 0x7c0) >> 6)).toString(16);
s0 += "%" + (0x80 + (u & 0x3f)).toString(16);
}
}
}
}
return s0;
}
